Question

Na2S2O3 + I2 gives Na2S4O6 + NaI​

Answer 1

Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method. here we see iodine , I2 is reduced (as oxidation number changes from 0 to -1) and sulphur is oxidised. ( as oxidation number of s changes from +2 to +2.5).

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Answer 2

Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method. here we see iodine , I2 is reduced (as oxidation number changes from 0 to -1) and sulphur is oxidised. ( as oxidation number of s changes from +2 to +2.5).

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