Question

Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method. here we see iodine , I2​

Answer 1

Answer:

Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method. here we see iodine , I2 is reduced (as oxidation number changes from 0 to -1) and sulphur is oxidised. ( as oxidation number of s changes from +2 to +2.5).

Answer 2

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Hi chinnu sis :)

I already gave my answer in your first question see

Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method. here we see iodine , I2 is reduced (as oxidation number changes from 0 to -1) and sulphur is oxidised. ( as oxidation number of s changes from +2 to +2.5).

Real answer is in your first question:)