Chemistry, asked by adarshadith05, 4 months ago

Na2SO4 + Bacl2 -- BaSO4 + 2NaCl

a)Which substance is soluble in water among the products?

b)Which substance is the white precipitate?

c) Does the white precipitate dissolves when dilute HCl [Hydrochloric Acid] is added to it?


Answers

Answered by Steph0303
70

Answer:

The given reaction is a double displacement reaction.

Reaction:

  • Na₂SO₄ + BaCl₂ → BaSO₄ + 2 NaCl

i ) NaCl, which is also known as common salt is the only substance which is soluble in water.

ii ) The White coloured precipitate obtained after the reaction is nothing but BaSO₄.

iii ) The reaction of the White Precipitate with Dilute HCl is given as:

  • BaSO₄ + HCl → BaCl₂ + H₂SO₄

BaSO₄ doesnt dissolve in diluted HCl as it requires high concentration of H⁺. But since the question is given with dilute HCl, the white precipitate is insoluble. But the product it forms, which is BaCl₂, is soluble with water.

Answered by ItzMrAlcohol
37

Answer:

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On adding dilute hydrochloric acid to the reaction mixture, white precipitate disappears

Explanation:

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