Na2SO4 minus(-)
draw a lewis dot structure?
don't spam the question...
Anybody know the answer......
Answers
Answered by
4
Answer:
For
S
O
2
−
4
, a reasonable Lewis structure to accommodate the 32 electrons is.....
(
O
=
)
2
S
(
−
O
−
)
2
, and clearly this is a derivative of the parent
sulfuric acid
, .....
(
O
=
)
2
S
(
−
O
H
)
2
. Given this Lewis structure, there are 6 valence electrons associated with the doubly bound oxygens (and hence these are neutral), 6 valence electrons with the central sulfur (and hence a neutral sulfur), and 7 valence electrons associated with each singly bound oxygen atoms, and hence these centres bear the 2 required formal NEGATIVE charges.
Note that all the oxygen atoms are equivalent, and we could even propose a Lewis structure of
2
+
S
(
−
O
−
)
4
.....
(
O
=
)
2
S
(
−
O
−
)
2
is a more conventional representation.
hope it's helpful,
follow me
Similar questions