NaBr + H2so4
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2 NaBr (aq) + 2 H2SO4 (aq) → Na2SO4 (aq) + Br2 (aq) + SO2 (aq) + 2 H2O (l)
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Explanation:
NaCl is a volatile solid. Less volatile liquid H2SO4 displaces the more volatile sodium chloride and hence there is no changed in oxidation state. Due to this it becomes a simple displacement reaction asNaCl + H2SO4
-->NaHSO4 +HClIn case of NaBr, Br- acts as reducing agent fr H2SO4 and the sulphuric acid is reduced to sulphr ioxide by bromide ion which itself gets oxideised to give bromine free molecule.
2NaBr + 2H2SO4 --> NaHSO4 + Br2 + SO2 + 2H2O.
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