Question

NaCl solution was added to AgNO3 and a product containing 10 g of weight was formed as the product.

Answer 1

The above has the equation of your question

Answer 2

Answer:

Mass of NaCl = 0.0699 × 58 = 4.054 grams

Mass of AgNO³ = 0.0699 × 170 = 11.883 grams

Explanation:

Let's first write down the equation for the reaction as follows:

NaCl + AgNO₃ -------> NaNO₃ + AgCl

Remember, AgCl is insoluble, and so, it is collected as a precipitate.

So, the mass of the precipitate is 10 grams.

From this, we can get the mass of reactants that was initially there.

Molar mass of NaCl = 58, AgNO₃ = 170, AgCl = 143

Moles of AgCl produced = 10/143 = 0.0699 moles

Moles of NaCl = Moles of AgNO₃ = Moles of AgCl

Mass of NaCl = 0.0699 × 58 = 4.054 grams

Mass of AgNO³ = 0.0699 × 170 = 11.883 grams