Math, asked by Medhani272007, 10 months ago

Nafisa is twice as old as Sakina. Five years ago her age was three tmies Sakina's age. Find their present ages.

Answers

Answered by anshikajais2001
4

Answer:

Let there ages be x and y respectively.

Given that

x=2y....(i)

and

x-5=3(y-5)

x-5=3y-15

x-3y=-15+5

x-3y=-10...(ii)

Putting valueof x in ii,

2y-3y=-10

-y=-10

y=10

thus

x=2y

x=2*10

x=20

Step-by-step explanation:


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