Question

Nafisa is twice as old as Sakina. Five years ago her age was three times Sakina's age. Find their present ages.

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Answer 1

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Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

Sakina is 10 Years old and Nafisa is 20 years old presently.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Nafisa's present age = twice as old as Sakina.

Five years ago Nafisa was three times Sakina's age.

To Find :

Their present ages

Solution :

Consider the present ages as -

• Sakina as x
• Nafisa as 2x

Ages Before 5 years -

• Sakina = x - 5
• Nafisa = 2x - 5

According to the question -

• Nafisa's age five years ago = three times Sakina's age.

★ 2x - 5 = 3(x - 5)

$\longrightarrow$ 2x - 5 = 3(x - 5)

$\longrightarrow$ 2x - 5 = 3x - 15

$\longrightarrow$ 2x - 3x = -15 + 5

$\longrightarrow$ -x = -10

$\longrightarrow$ x = 10

Sakina's age = 10 Years

$\rule{300}{1.5}$

★ Value of 2x

$\longrightarrow$ 2 × 10

$\longrightarrow$ 20

Nafisa's age = 20 years

$\therefore$ Sakina is 10 Years old and Nafisa is 20 years old presently.