Chemistry, asked by officialhimanshu19, 1 day ago

NahPO4 oxidation number for P

Answers

Answered by RohitVaishnavv
0

Answer:

The Correct Answer is 5

Explanation:

Let X be the oxidation number of P in NaH_{2}PO_{4}

​ The oxidation numbers of Na, H and O are +1, +1  and −2 respectively.

+1+2(+1)+X+4(−2)=0

3+X+−8=0

X+−5=0

X=+5

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