Nahush is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 30 m, 20 m and 14 m respectively. From each can of paint 200 m sq. of area is painted. How many cans of paint will she need to paint the room
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Area to be painted = area of the walls + area of ceiling
=2(hl+hb)+lb
=[2×(7×15+7×10)+(15×10)]=500 sq m
No. of cans required = 100500 =5
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.
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