Question

Nai koi problem Nahi hai
btw Good Evening, how are you Lol.
btw merko ye solve karke dedo na

Don't spam please
$3x {}^{2} - 4 \sqrt{3} x + 4 = 0.$
solve please​

Answer 1

Answer:

For a quadratic equation ax² + bx + c =0, the term b² - 4ac is called discriminant (D) of the quadratic equation because it  determines  whether the quadratic equation has real roots or not ( nature of roots).

D=  b² - 4ac

So a quadratic equation ax² + bx + c =0, has

i) Two distinct real roots, if b² - 4ac >0 , then x= -b/2a + √D/2a  &x= -b/2a - √D/2a

ii) Two equal real roots, if b² - 4ac = 0 , then x= -b/2a or -b/2a

iii) No real roots, if b² - 4ac <0

SOLUTION:

Given: 3x² – 4√3x + 4 = 0

On Comparing it with ax² + bx + c = 0, we get

a = 3, b = -4√3 and c = 4

Discriminant(D) = b² – 4ac

D= (-4√3)² – 4(3)(4)

D= 16 × 3 - 48

48 – 48 = 0

As , b² – 4ac = 0,

Hence, the given quadratic equation has  real and equal roots.

Hope it helps you!!

:)

Answer 2

Answer:

please reffer the above attachment

Step-by-step explanation:

heach method use karun baki solve kar ok

aaj yeanar aashil tar 12.30 la yea ok

see you soon