Question

Naimish present age, is three times his daughter's present age and nine-thirteenth of his mother's present age. the sum of the present age of all of them is 125 years. what is the difference between the naimish's daughter present age and naimish's mother present age?

Answer 1

Let the age of Naimish = x
                                    x = 3 times daughter's age
=>         daughter's age = $\frac{x}{3}$
               mother's age  = $\frac{13}{9} x$

x + $\frac{x}{3}$ + $\frac{13}{9} x$ = 125
                                        $\frac{13x+3x+9x}{9} = 125$
                                                                  $25x = 125*9$
                                                                              x = 45

                                                      Daughter's age = $\frac{45}{3}$
                                                                                 = 15
                                                          Mother's age = $\frac{13}{9}*45$
                                                                                 = 13*5
                                                                                 = 65

Mother's age - Daughter's age = 65 - 15
                                                    = 50