Question

Naman and Aman decided to play marble games. They were having 12 marbles in a box with them. They numbered the marbles from 1 to 12. Aman decided to take all even numbered marbles and Naman took odd numbered marbles.

(a) What is the probability that Aman will win a point when they draw a marble from the box (What is the probability of drawing an even numbered marble)?

(b) If Naman's birthday falls on 7th April and he believes that his birth date is lucky for him. What is the probability that he draws his lucky numbered marble? ​

Answer 1

Answer:

part a answer : 1/2

Step-by-step explanation:

p (drawing an even numbered marble) : 6/12

which will be 1/2 after we do cutting of 6/12

Answer 2

Step-by-step explanation:

Total number of marbles = 6

So n(s) = 6

Number of marbles marked with 2 = 1

n(e) = 1

Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\Total number of outcomesNumber of favourable outcomes 

=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}= n(s)n(e) = 61

ii) Total number of marbles = 6

n(s) = 6

Number of marbles marked 5 = 1

n(e) = 1

Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\Total number of outcomesNumber of favourable outcomes 

=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}= n(s)n(e) = 61