Math, asked by smankirat5u, 9 months ago

Naman missed the bus by 3 minutes, when
walked at 4 km/h. However he reached the
bus stand 3 minutes early when walked at
5 km/h. Find the distance of the bus stand
from his house.​

Answers

Answered by dhairyadr7
6

Step-by-step explanation:

Brainly.in

2000m

Let in time t ,I reach the bus stand with a speed v m/min. and distance between home and bus stand is x meter(m).

4 km/hr = 4*1000/60 = 200/3 m/min

5 km/hr = 250/3 m/min

t = x/(200/3) - 3

t = x/(250/3) + 3

x/(200/3) - 3 = x/(250/3) + 3

x = 2000m

time = 2000/(200/3) - 3 = 27min.

speed = 2000/27 m/min

hence distance between bus stand and home = 2000m

Answered by xcristianox
6

Let in time t ,I reach the bus stand with a speed v m/min. and distance between home and bus stand is x meter(m).

4 km/hr = 4*1000/60 = 200/3 m/min

5 km/hr = 250/3 m/min

t = x/(200/3) - 3

t = x/(250/3) + 3

x/(200/3) - 3 = x/(250/3) + 3

x = 2000m

time = 2000/(200/3) - 3 = 27min.

speed = 2000/27 m/min

Hence distance between bus stand and home = 2000m

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