Namaskaram!
In figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.
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Answered by
5
Answer:
angle CBD is 60 degree of triangle
Step-by-step explanation:
I send you answer tomorrow to edit answer okk
Answered by
3
Answer:
triangle BPD is a isosceles triangle so
le the two angles be x
ATQ, x+x+120=180(angle some property)
2x+120=180
2x=180-120
x=60/2
=30
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