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1. Solve the following sets of simultaneous equations:
x+3y=1,
x + 3x + 5y = 20
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X+3y=1
X=1-3y—————-(1)
X+3x+5y=20
4x+5y=20
4(1-3y)+5y=20
4-12y+5y=20
4-20=12y-5y
-16=7y
Y=-16/7
Substituting value of y in eq(1),
X=1+3(-16/7)
X=1-48/7
X=(7-48)/7
X=41/7
X=1-3y—————-(1)
X+3x+5y=20
4x+5y=20
4(1-3y)+5y=20
4-12y+5y=20
4-20=12y-5y
-16=7y
Y=-16/7
Substituting value of y in eq(1),
X=1+3(-16/7)
X=1-48/7
X=(7-48)/7
X=41/7
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