Question

name of (NH4)2[Co(SCN)6]

Answer 1

Answer:

Ammonium hexathiocyanatocobaltate(IV)

Explanation:

(1) Name the cation first. That part's easy: NH4(+) = ammonium

(2) The anion is complex. Ligands are always named before the metal to which they are coordinated. In this case, there are six thiocyanate (SCN(-)) ligands coordinated to one cobalt(IV) ion.

(3) Greek prefixes (mono-, di-, tri-, tetra-, penta-, hexa-, etc) are used to indicate the number of each kind of ligand bound to the metal ion.

(4) The names of negative ligands always end in -o, so thiocyanate becomes thiocyanato-

(5) The metal's name is changed to end in -ate.

(6) Write the oxidation number of the metal after its name as a Roman numeral in parentheses. There are two ammonium ions, each of which carries a +1 charge. There are six thiocyanate ions, each with a -1 charge. If the compound is neutral as a whole, then the cobalt ion MUST have a +4 oxidation number.

Answer 2

Answer:

coc1+ 4nh4 scn

Explanation:

1) nh4(+)=ammonium

2) (snc(-))= ligands coordinate to cobalt(iv) ion