Question

name of two integers whose product is -18 and whose quotient is -2.

Answer 1

✔✔heya here is ur answer!!

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let ua take the numbers as x and y.

given , x× y = -18 and x/y = -2

=> x = -2y

substitute x in x×y = -18

=> -2y×y = -18

=> -2y^2 = -18

=> y^2 = -18/-2

=> y^2 = 9

=> y = 3

substitute y in eqn

=> x×3 = -18

=> x = -18/3

=> x = -6

THANK YOU ✌✌

HOPE IT HELPS YOU ☺☺☺

Answer 2

Let the numbers be x and y.

Given that product of two integers is -18.

xy = -18

x = -18/y ------ (1)

Given that Quotient of two numbers is -2.

= > (x/y) = (-2)

= > (-18/y)/y = -2

= > -18/y^2 = -2

= > -18 = -2y^2

= > y^2 = 9

= > y = +3,-3 ----- (1)

When y = +3:

x = -18/y

x = -18/3

x = -6.

When y = -3:

= > x = -18/-3

= > x = 6.

Therefore, the integers are : 6,3 and -6,-3 (or) 6,-3 and -6,3

Hope this helps!