Question

Name some hydrocarbonds whose carbons and hydrogen are distinguishing to solve empirical formula and molecular formula question. Like benzene, Ethene.....

Answer 1

MoleculeStep 1 
CnH2n +2Step 2 
AdjustStep 3 
SubtractStep 4 
DivideHDIBenzene 
C6H614614 - 6 = 88/2 = 44Pyridine 
C5H5N125–1 = 412 - 4 = 88/2 = 44Ethylamine 
C2H7N67–1 = 66 – 6 = 0 02-Butanol 
C4H9OH101010-10 = 0 0Chlorobenzoic acid C7H5O2Cl165+1=616-6 = 1010/2=55