Question

name the altutudes of ∆PQR​

Answer 1

Answer:

Step-by-step explanation:

Steps of construction :

(i) Draw any acute angled ∆PQR.

(ii) With P as centre, draw an arc that cut the side QR at X and Y.

(iii) With X as centre and radius more than half of XY, draw an arc below QR. With Y as centre and same radius draw another arc that cut the previous arc at A.

(iv) Join PA that intersect QR at L. So, PL is the altitude on side QR.

In the same manner, draw QM⊥PR and RN⊥PQ.

Hence, ∆PQR is the required triangle with altitudes PL, QM and RN on sides QR, RP and PQ respectively with O as the point of concurrence of all the three altitudes.

Answer 2

Answer:

Hi,

Solution: steps of construction

Draw the line QR of any length.

At Q draw an acute angle (i.e. greater then 0 degree and less then 90 degree),with the help of protector and scale.

draw a line from Q with the given angle ,mark the point P.

Join P and Q. Δ PQR is formed.

To draw altitudes , draw lines from all points i.e. PQR,join them with dashed lines.where all lines meet mark that point as O.

Hope it helps you.

Step-by-step explanation:

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