Question

name the elements whose outermost electroinic configuration are i) 2p3 ii) 4s2​

Answer 1

(i) (a) The electronic configuration of H−is  1s2

(b)The electronic configuration of Na+ is 1s22s22p6

(c)The electronic configuration of O2− is 1s22s22p6

(d) The electronic configurations of F− is 1s22s22p6

(ii) The atomic numbers of elements whose outermost electrons are represented by (a)3s1(b)2p3and(c)3d1are 11 (Na), 7 (N) and 21 (Sc) respectively.

(iii) The following configurations indicates

(a) [He]2s1 (b) [Ne]3s23p3 (c) [Ar]4s23d1

(a) Li (Z=3), (b) P(Z=15) and (c) Sc Z=21) respectively

Answer 2

Answer:

nitrogen and calcium

Explanation:

1s2s22p3 is total 7 electrons so it is nitrogen

1s22s22p63s23p64s2 is total 20 electrons so it is calcium

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