Name the following.
family with parents, two some and two daughters______.
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In a given family two daughters must sit on either side of father. This combination is possible in 2 different ways i.e. 1st daughter on left 2nd daughter on right and vice versa.
Remaining wife and 2 sons can sit in blank chairs in 3×2×1=6 different ways.
Total ways of sitting = 2×6 = 12 ways.
(*In this problem, We have assumed rotation doesn't matter.)
Explanation:
pls mark rainlisat
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