Question

name the main product formed when


Ethanoic acid is treated with sodium bicarbonate

ethanol is heated with alkaline KMnO4 solution

ethyl ethanoate is treated with NaOH solution


also write the chemical equation for each of the above reaction

Answer 1

WHEN ethanoic acid treated with sodium bicarbonate it wll form soap carbon dioxide and water
CH3COOH+NAHCO3=CH3COONA+H20+CO2
when etanol heated  with alkaline KMNO4 it will form ethene and water
CH3CH2OH+KMNO4+HEAT=CH2CH2+H2O
when ethyl ehanoate teated with NAOH it will form soap and thanol
CH3COOCH3CH2+NAOH=CH3COONA+CH3CH2OH

Answer 2

I)CH3COONa+CO2+H20
(sodium eythanoate , carbon dioxide and water)

ii) CH3COOH+H2O
(ethanoic acid and water)

(III)CH3COOH+C2H5OH
(ethanoic acid and ethanol)