Question

Name the name the substance of sides and reduced pbs + 4 h2 o2 pbso4 + 4 h2o

Answer 1

Answer:

Explanation:

I guess you mean the following equation:

PbS+2H202 →PbSO4+4H2O

Oxidation state of each element in a compound:

PbS-

Pb - +2

S - -2

2H202-

H - +1

O - -1

PbSO4-

Pb - +2

S - +6

O4 - -2

H20

H - +1

O - -2

As oxidation state of Pb in reactant side decreases from -2 to +6 in product side it is reducing agent and oxidation reaction.[ Oxidation: loss of electron ]

As oxidation state of oxide in reactant side increases from -1 to -2 in product side it is oxidizing agent and reduction reaction. [ Reduction: gain of electron ]

Answer 2

Answer:

The following reaction's substance is al+Fe(550celcius )