Name the organic compound prepared by each of the following reactions: (i) CH3 COONa + NaOH CaO →∆ (ii) CaC2 + H2O → (iii) C2H5Br + KOH (alc) → (iv) C2H5Br + KOH (aq) → (v) C2H5OH + CH3COOH 2 4 Con H SO . →
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1. Methane is formed in the first reaction.
2. Ethyne is formed in the second one.
3. Ethene is formed in the third one.
4. Ethyl alcohol is formed in the fourth one.
5. Ethyl acetate is formed in the fifth one.
2. Ethyne is formed in the second one.
3. Ethene is formed in the third one.
4. Ethyl alcohol is formed in the fourth one.
5. Ethyl acetate is formed in the fifth one.
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Answer:
1. Methane is formed in the first reaction.
2. Ethyne is formed in the second one.
3. Ethene is formed in the third one.
4. Ethyl alcohol is formed in the fourth one.
5. Ethyl acetate is formed in the fifth one.
Explanation:
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