Question

Name the oxidizing and reducing agent in the following reaction : 2H2S+SO2=2H2O+3S​

Answer 1

Answer:

Explanation:

oxidising agent is SO2 and reducing agent is H2S.

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Answer 2

Answer:

$H_{2} S$ is the reducing agent while $SO_{2}$ is the oxidizing agent.

Explanation:

Reducing agent:

• In a chemical process, a reducing agent, also known as a reductant, loses electrons and is oxidized.
• The electron donor is a reducing substance, which is normally in one of its lower oxidation states.
• A reducing substance undergoes oxidation because of the redox reaction's electron loss.

Oxidizing agent:

• In a redox chemical process, an oxidizing agent is a material that obtains or "accepts" or "receives" an electron from a reducing agent
• It also known as an oxidant, oxidizer, electron recipient, or electron acceptor.

The chemical reaction is,

$2H_{2} S + SO_{2} - > 2H_{2} O + 3S$

In $SO_{2}$, Sulfur dioxide is converted to Sulphur when oxygen is removed.

In $H_{2} S$, hydrogen sulfide is oxidized to Sulphur when hydrogen is removed

$H_{2} S$ undergoes oxidation while $SO_{2}$ will undergo reduction

Therefore,

$H_{2} S$ act as a reducing agent.

$SO_{2}$ act as a oxidizing agent

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