Question

Name the Quadratic polynomial whose zeroes are 4 and -4.

Answer 1

Step-by-step explanation:

Let Alpha be 4.

Beta be -4.

Formula - x^2-(Alpha + Beta)x + Alpha × Beta .

x^2-(4+(-4))x +4×-4

x^2-(0)x+(-16)

x^2-0-16

• The Required Quadratic Polynomial is

x^2-16

Answer 2

The Quadratic polynomial is P(x) = x² - 16

Step-by-step explanation:

The zeros are 4 and -4

Factor Theorem: If a is the zero of a polynomial then (x-a) must be a factor.

Using this theorem, we can conclude that (x-4) and (x+4) are the factors of the polynomial.

Therefore, the quadratic polynomial is given by

P(x) = (x-4) (x+4)

On multiplying, we get

P(x) = x²+4x - 4x -16

P(x) = x² - 16

#Learn More:

Find the polynomial whose zeros are squares of the zeroes of the polynomial 3x² + 6x – 9.

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