Question

Name the reagents used to convert phenol into(i) picric acid(ii) 2, 4, 6 - Tribromophenol(iii) Benzene(iv) o - phenol sulphonic acid.

Answer 1

1.HNO3+H2SO4
2.no reagent just Br3
3.zinc dust
4.CCl4+HCL

Answer 2

Answer:

Explanation:

Given :

T = 435.5 dyne/cm = 0.4355 N/m,

θ = 14

0

ρ = 13600 kg/m³  

d = 1 cm

∴ r = 0.5 cm

= 5 × 10⁻³ m  

T = rh ρ g/ 2 cos θ  

h = 2T cos θ/ r g ρ  

∴ h = 2 x0.4355x cos140⁰/ 5 x10⁻³x 13600 x9.8

= 0.8710x cos( 90 + 50  )/ 5x 13.6 x9.8  

=0.8710( –sin 50  ) /5x 13.6 x9.8

=–0.8710x 0.7660/ 68.0x 9.8  

= – 1.001 × 10⁻³m  

∴ h = – 1.001 mm

here  Negative sign indicates that mercury level will be lowered by 1.001 mm.

Hence to get correct reading h = 1.001 mm has to added.  

∴ h = 1.001 mm

1.HNO3+H2SO4

2.no reagent just Br3

3.zinc dust

4.CCl4+HCL