Question

name the rule that gave the direction of induced current?​

Answer 1

Answer •°•°•°•°•°•°••°•°•

Fleming's right-hand rule (for generators) shows the direction of induced current when a conductor attached to a circuit moves in a magnetic field.

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Answer 2

Given :-

Mass of the water lifted = 200 kg

Height carried by the pump = 6 m

Time taken to carry = 10 sec

To Find :-

The power of the pump.

Analysis :-

Here we are given with the mass, height and time taken to carry the water.

Firstly find the work done by substituting the given values in it's respective formula.

Then find the power done by substituting the values such that power is equal to work done divided by the time taken.

Solution :-

We know that,

m = Mass

h = Height

w = Work done

t = Time

g = Gravity

p = Power

Using the formula,

\underline{\boxed{\sf Work \ done=Mass \times Gravity \times Height}}

Work done=Mass×Gravity×Height

Given that,

Mass (m) = 200 kg

Gravity (g) = 10 m/s

Height (h) = 6 m

Substituting their values,

⇒ w = mgh

⇒ w = 200 × 10 × 6

⇒ w = 2000 × 6

⇒ w = 12000 J = 1.2 × 10⁴ J

Using the formula,

\underline{\boxed{\sf Power=\dfrac{Work \ done}{Time \ taken} }}

Power=

Time taken

Work done

Given that,

Work done (w) = 1.2 × 10⁴ J

Time (t) = 10 sec

Substituting their values,

⇒ p = 1.2 × 10⁴/10

⇒ p = 1200 W

Therefore, the power of the pump is 1200 W.