Question

name the substance oxidized reduced oxidizing agent and reducing agent in the following reaction H2 O2 + 2 k L =2 k o h + I2​

Answer 1

Explanation:

H2O2 (aq) + 2 KI (aq) → I2 (s) + 2 KOH (aq)

This is an oxidation-reduction (redox) reaction:

2 I-I - 2 e- → 2 I0

(oxidation)

2 O-I + 2 e- → 2 O-II

(reduction)

KI is a reducing agent, H2O2 is an oxidizing agent.

This is a precipitation reaction: I2 is the formed precipitate.

Answer 2

Answer:

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