Question

Name the two altitudes of a Triangle XYZ, Right-angled at Y.

Answer 1

Answer:

Diagonal BD ⊥ AB

BD² = AD² - AB²

⇒ BD² = 10² - 6²

⇒ BD² = 100 - 36

⇒ BD² = 64

⇒ BD = 8 cm

Area of Triangle ABD

= (1/2) × 6 × 8 = 24 cm²

Divided into two halves

= 24/2 = 12 cm²

ΔBCD has 5 , 5 & 8 cm

S = (5 + 5 + 8)/2 = 9

Area of ΔBCD = √9(9-5)(9-5)(9-8)

     = √9 × 4 × 4 × 1 = 12 cm²