Question

name the type of a quadrilateral having vertices A(-1,0), B(3,1), C(2,2) and aD(-2,1)​

Answer 1

Answer:

A. = 2nd quadrant

B = 1st quadrant

C = 1st quadrant

D = 2nd quadrant

It forms

Here AB =

(3+1)

2

+(1−0)

2

=

17

BC=

(2−3)

2

+(2−1)

2

=

2

CD=

(−2−2)

2

+(1−2)

2

=

17

AD=

(−2+1)

2

+(1−0)

2

=

2

Here,AB=CD and BC=AD

Therefore its a parallelogram