Name the type of allele discussed in dogs example
Answers
Answer:
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Explanation:
The four alleles of this gene in order of dominance are: melanistic mask (Em), grizzle (Eg), black (E) and red (e). K (dominant black) locus. This gene controls dominant black, brindle, and fawn colors. This relatively new locus includes colorations previously linked to other genes like Agouti.
Answer:
Modern dog breeds have a wide range of coat colors, patterns, textures and lengths. Knowledge of the genetics of canine coat coloring and patterning[1] and coat texturing and length[2] has improved a great deal in recent years.
Dog coat color is governed by how genes are passed from dogs to their puppies and how those genes are expressed in each dog. Dogs have about 19,000 genes in their genome but only a handful affect the physical variations in their coats. And the usual rules apply—most genes come in pairs, one from the dog’s mother and one from its father. Genes of interest have more than one version, or allele. Usually only one or a small number of alleles exist for each gene. So, at any one gene locus a dog will either be homozygous, that is, the gene is made of two identical alleles (one from its mother and one its father) or heterozygous, that is, the gene is made of two different alleles (again, one inherited from each parent).
To understand why a dog’s coat looks the way it does based on its genes requires an understanding of a handful of particular dog coat genes and their alleles. For example, if you wanted to find out how a black and white greyhound that seems to have wavy hair got its coat, you would want to look into the dominant black gene with its K and k alleles, the (white) spotting gene with its multiple alleles, and the R and r alleles of the curl gene.