Name the type of quadrilateral formed by the points : ( - 1 , 1 ) , ( 2 , - 2 ) , ( 8
, 4 ) , ( 5 , 7 )
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1
Answer:
A(4,5),B(7,6),C(4,3),D(1,2)
AB=
(4−7)
2
+(5−6)
2
AB=
10
BC=
(7−4)
2
+(6−3)
2
BC=
18
CD=
(4−1)
2
+(3−2)
2
CD=
10
AD=
(4−1)
2
+(5−2)
2
AD=
18
AB=CD=
10
AD=BC=
18
BD=
(7−1)
2
+(6−2)
2
BD=
42
Since the opposite sides are equal and diagonals are unequal.
So the quadrilateral would be a parallelogram.
Step-by-step explanation:
Therefore, the quadrilateral formed by these set of points is a parallelogram. Note: In this question, we have the most basic coordinate geometry formula, that is distance formula, which is for two points, (x1,y1) and (x2,y2)=√(x2−x1)2+(y2−y1)2.
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