Question

name the type of triangle formed(if any) by the points A(4, 6), B(2, 3) and C(6, 9)​

Answer 1

Answer:

isosceles triangle

Step-by-step explanation:

we need to find the distance between AB BC and CA. Here two sides of a triangle are equal then it is isosceles triangle.

Answer 2

Answer:

Step-by-step explanation:

The points are

A(4, 6), B(2, 3) and C(6, 9)​

$AB = \sqrt { (4-2)^2+(6-3)^2)} =\sqrt{4+9} =\sqrt{13} =3.6\\\\BC = \sqrt { (6-2)^2+(9-3)^2)} =\sqrt{16+36} =\sqrt{42}=6.48 \\\\CA = \sqrt { (6-4)^2+(9-6)^2)} =\sqrt{4+9} =\sqrt{13}=3.6\\\\We\ observe \ that :\\\\AB +CA=3.6+.36=7.2 > BC ( 6.48)\\\\Thus \ a \ triangle \ is \ possible \\\\Also \ AB=CA\\\\\bf Thus \ \triangle \ ABC \ is \ an \ isosceles \ triangle$