Question

name the type of triangle PQR formed by the point p(√2,√2) ,q(-√2,-√2),R(-√6,√6)

Answer 1

first you find distance between two point
pq=root(16)
=4
qr=root {(root6+root 2)^2+(root 6-root 2)^2}=4
rs=root {(root6+root 2)^2+(root 6-root 2)^2=4
here we look
pq=qr=rs
so this pqr triangle is equilatral triangle