Question

Name
WORKSHEET 4
Class6
Sec-c
3. Playing with Numbers
1.
Find the greatest number that will divide
328, 436 and 544 leaving remainder 7, 8 and
9 respectively,
Solution:
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Answer 1

Answer:

107 is the greatest number that will divide 328, 436 and 544 leaving remainder 7, 8 and 9 respectively

Answer 2

Answer:-

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 - 7 = 321=> 436 - 8 = 428=> 544 - 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively