Question

namstey!!

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A machine gun fires a bullet of mass of 40g with a velocity 1200m/s . the man holding kr can exert minimum force 144N on the gun . How many bullets can he fire per second at the most ?

Answer 1

40 g = 0.04 kg

144 N = 0.04 * a

a = 3600 m/s^2

per second = a/t = v = 3600 m/s

but each bullet can travel at 1200 m/s

so no of bullets is 3600/1200

= 3 bullets

Answer 2

$\star \bold \blue{hlo \: dear}$_

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$\bold\green {solution}$ :-

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Given :- mass of bullet = 40 g

velocity = 1200 m/s

force exerted by man = 144N

Let n be the number of bullets that the man can fire in one second

•°• change in momentum per second

=> n × mv = F

[ m = mass of bullets , v = velocity ] {°•° F is the force )

°•° n = f /mv = 144 * 1000 / 40 * 1200 n = 3. 3 bullets he can fire per second

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