Question

Namstey !

Question from iit jee main 2003

from permutations and combinations
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The number of ways in which 6 men and 5 women can dine at a round table if no two women are a sit together is given by

(a ) 6! × 5!
(b) 6× 5
(c) 30
(d) 5× 4

Answer 1

hey mate here is your answer

option (a) is correct

plz follow me

Answer 2

$\bold \red{hello \: friends} \:$

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$\bold \green{solution}$

No. of ways in which 6 men can be arranged at a round table = ( 6 - 1 ) = 5 !

now women can be arranged in 6P5

=> 6 !

Total number of ways = 6 ! × 5!

Answer option , ( a ) is correct answer

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