Nancy is standing at point a facing north. she walks 50 meters to her right and takes a left turn and walks another 40 meters, then she walks 30 meters to her left again and then 20 meters to her right. ln which direction is she standing from her starting point?
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NORTH DIRECTION
1ST AT NORTH
2ND EAST
3RD NORTH
4TH WEST
5TH NORTH
1ST AT NORTH
2ND EAST
3RD NORTH
4TH WEST
5TH NORTH
Answered by
4
Hey dear,
◆ Answer-
s = 63.24 m facing north
◆ Explanation-
[Refer to the figure]
As we can see, Nancy is standing at point A facing north.
Her movement should be tracked with the help of map diagram like I've posted.
From the figure, we can see that, Nancy is standing at destination point facing north again.
Let,
a = total vertical distance
b = total horizontal distance
Total distance from starting point is-
s = √(a^2 + b^2)
s = √(60^2 + 20^2)
s = √(3600+400)
s = √(4000)
s = 63.24 m
Therefore, Nancy is standing at destination point facing north 63
24 m from starting point.
Hope it helps...
◆ Answer-
s = 63.24 m facing north
◆ Explanation-
[Refer to the figure]
As we can see, Nancy is standing at point A facing north.
Her movement should be tracked with the help of map diagram like I've posted.
From the figure, we can see that, Nancy is standing at destination point facing north again.
Let,
a = total vertical distance
b = total horizontal distance
Total distance from starting point is-
s = √(a^2 + b^2)
s = √(60^2 + 20^2)
s = √(3600+400)
s = √(4000)
s = 63.24 m
Therefore, Nancy is standing at destination point facing north 63
24 m from starting point.
Hope it helps...
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