Question

Nandini and Bhoomika are very good friends They decided to play a game Nandini asked Bhoomika to think of a number and subtract 2/3 from it Then she asked to multiple the result by 6 again she asked to add 8 in the result Now Bhoomika said, The number I obtained is 7 times the same number I thought of A) Write the equation to find the number that Bhoomika thought of. Also find the number ​

Answer 1

Answer:

Equation: ((x-2/3)×6)+8 = 7x

Number=4

Step-by-step explanation:

Let the number be x

So, According to Question

((x-2/3)×6)+8 = 7x

=> (((3x-2)/3)×6)+8 = 7x

=> ((3x-2)×2)+8 = 7x

=> 6x-4+8 = 7x

=> x = 4

Answer 2

The equation to find the number that Bhoomika thought of is $\bf 6\left(x - \frac{2}{3} \right)+ 8 = 7x$. The number is 4.

Given:

Nandini and Bhoomika are very good friends They decided to play a game Nandini asked Bhoomika to

• Think of a number and subtract 2/3 from it.
• Then she asked to multiple the result by 6
• Again she asked to add 8 in the result.
• Now Bhoomika said, The number I obtained is 7 times the same number I thought of.

To find : Write the equation to find the number that Bhoomika thought of. Also find the number.

Solution:

Let us assume the number bhoomika though is x.

Step 1:

According to the statement of Nandini, she has to subtract 2/3.

So,

$x - \frac{2}{3}$

Step 2:

According to the next statement of Nandini, she has to multiply it by 6.

$6\left(x - \frac{2}{3} \right)$

Step 3:

According to the next statement of Nandini, she has to add 8.

$6\left(x - \frac{2}{3} \right) + 8$

Step 4:

ATQ

$6\left(x - \frac{2}{3} \right) + 8 = 7x$

simplify by BODMAS rule,

Open bracket first (or multiply 6)

$6x - 4 + 8 = 7x$

Perform addition/subtraction

$6x + 4 = 7x$

Take x in LHS and constant term to RHS

$6x - 7x = - 4$

or

$- x = - 4$

cancel (-) from both sides.

$\bf x = 4$

Therefore,

The number bhoomika thought of is 4.

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