NaOH aqueous solution is labeled as 10% by(w/v) density of the solution is 1.02g/ml then the more fraction of the solute is
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10% of NaOH and 90% of water.
10% NaOH contains 100 g in 1 liter of Solution.The no.of moles of NaOH=100/40 =2.5mole.
The no.of moles of water in 1 liter of Solution=900/18=50 moles.
No.of moles of Solute+Solvent =2.50+50 =52.50 moles.
So the mole fraction of the Solute= No.of moles of Solute/Total moles=2.5/52.5=0.0476
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