Question

NaOH disalue in
om
3.10 of heater, calcullate the
molality
NaoH solution​

Answer 1

Explanation:

It is given that the density of the solution is 1.110 g mL

−1

.

The concentration of sodium hydroxide solution is 3.0 molal.

This implies 1000 g of water has 3 moles of NaOH.

3 moles of NaOH =3×40=120 g of NaOH

Mass of solution =1000+120=1120 g

Volume of solution =

Density

Mass

=

1.11

1120

=1009 mL

Molarity =

Volume in L

Number of moles

=

1000

1009

3

=2.97 M

Hence, the molarity of the solution is 2.97 M