Naoh reacts with oxalic acid water of crystallization of oxalic acid reaction
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H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).
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