Question

NaOH solution [OH-] is 2.87 *10-4. Calculate the pH of solution
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Answer 1

Answer:

the p(OH-) = log (2.87 x 10^-4)

                  =  log (2.87) + log (10^-4)

                  =   0.457 - 4log (10)

                  =   0.457 - 4

                  =   -3.54

as you may know p(H) + p(OH) = 14

the p(H+) will be 14-3.54 = 10.46

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Answer 2

The pH of the solution  is 10.457

The pH of the solution is the measure of acidity or basicity of the solution.

Explanation:

 Given -The concentration of [OH-] is 2.87× 10⁻⁴

we have to find pH of solution =?

where the formula of pH=-log[H⁺] and

⇒pOH=-log[OH⁺]⇒pOH=-log[ 2.87× 10⁻⁴]

⇒pOH=3.54

⇒pH+pOH=14

⇒pH+3.54=14

pH =10.457

The calculated value ofOH is found to be10.457