naphthalene balls contains 93.71 carbon and 6.29 hydrogen. if the molar mass is 128 g/mol,calculate its molecular formula
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Assuming that is a mass amount, divide each proportion by the atomic weight of the component. Normalize to obtain the empirical formula and then use the molecular mass to determine the actual molecular formula.
93.9112=7.83 relative moles of carbon
6.291=6.29 relative moles of hydrogen
Ratio of C:H is 7.83:6.29 or 1.2. Nearest whole multiple is 5, resulting in ratio of 6:5. 6-C and 5-H would have a molecular weight of (6×12)+(5×1)=77 The actual molecular weight is 128, so the formula must be 12877=1.67×C6H5.
C10H8
93.9112=7.83 relative moles of carbon
6.291=6.29 relative moles of hydrogen
Ratio of C:H is 7.83:6.29 or 1.2. Nearest whole multiple is 5, resulting in ratio of 6:5. 6-C and 5-H would have a molecular weight of (6×12)+(5×1)=77 The actual molecular weight is 128, so the formula must be 12877=1.67×C6H5.
C10H8
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Answer:1
Explanation:emperical formula=c5h4
N=128/2=2
(c5h4)2
=c10h8
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