Physics, asked by ruwaydhakhan, 6 months ago

Naresh and Sharma went to agra through Yamuna - Expressway. Naresh

started the car and accelerated so high that the car was running at 110 km/h

within 12 seconds. Sharma stopped him from doing so and told him that

overspeeding on the road is a straight invitation to a life staking situation.

Though Naresh wanted the adventure of speeding, he was convinced by

Sharma.

a) Why do you think it is dangerous to drive fast on the road?

b) Which values of sharma appreciating?

c) Find Naresh’s car speed in m/s.

d) What is the acceleration of a car?​

Answers

Answered by SujalSirimilla
5

\LARGE{\bf{\underline{\underline{GIVEN:-}}}}

  • Initial velocity (u) = 0kmhr⁻¹ [Because car started from rest]
  • Final velocity (v) = 110kmhr⁻¹.
  • Time (t) = 12 seconds ⇒ (1/300) hours [Convert the units so that there is a common unit. To convert ].

\LARGE{\bf{\underline{\underline{TO:FIND:-}}}}

a) Why do you think it is dangerous to drive fast on the road?

b) Which values of Sharma appreciating?

c) Find Naresh’s car speed in m/s.

d) What is the acceleration of a car?​

\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}

a) Yes, it is dangerous to drive fast on the road because if we accelerate faster than the speed limit, the chances of having an accident are higher.

b) Sharma was careful, cautious, attentive, alert and vigilant . He had a lot of critical thinking skills.

c) Naresh's car was running at a speed of 110kmhr⁻¹. In order to convert kmhr⁻¹ into ms⁻¹, divide the speed value by 3.6.

\sf Speed(in \ ms^{-1})=\dfrac{110}{3.6}

\boxed{\sf{\red{Speed= 30.56 ms^{-1}}}}

d) We know that:

\sf{\red{Acceleration=\dfrac{v-u}{t} }}

Plug in the values.

\sf A=\dfrac{110-0}{\dfrac{1}{300} }

\sf A=110 \times 300

\boxed{\sf{\red{A=33000kmhr^{-2}}}}

Similar questions