Question

naresh is four times as old as his brother. after 10 years, he will be twice the age of his brother. what are their present ages?​

Answer 1

Answer:

Step-by-step explanation:

Let the present age of Naresh's brother be = x

Age of Naresh = 4x

Age of Naresh's brother after 10 years = x+10

Age of Naresh after 10 years = 4x+10

∴According to the question -:

Age of Naresh = Twice the age of his brother

4x+10 = 2(x+10)

2x = 10

x = 5

Therefor Age of Naresh is 20 and age of his brother is 5.

Answer 2

Given:

• Naresh is four times as old as his brother
• After 10 years, Naresh will be twice the age of his brother.

To Find:

Present ages of Naresh and his brother

Solution:

Let the present age of Naresh's brother be x.

Then, according to question

Present age of Naresh= 4x

After 10 Years

Age of Naresh= 4x+10

Age of Naresh's brother= x+10

Also, according to question

$\longrightarrow\mathrm{4x+10=2(x+10)}$

$\longrightarrow\mathrm{4x+10=2x+20}$

$\longrightarrow\mathrm{4x-2x=20-10}$

$\longrightarrow\mathrm{2x=10}$

$\longrightarrow\mathrm{x=\dfrac{\cancel{10}}{\cancel{2}}}$

$\longrightarrow\mathrm{x=5}$

So,

$\sf{Present\:age\:of\:Naresh's\:Brother=x=5\:years}$

$\sf{Present\:age\:of\:Naresh=4x=4(5)=20\:years}$

Hence, the present age of Naresh is 20 years and present age of Naresh's brother is 5 years.