Question

Natural gas is piped from the well at 300K and 400 kPa. The gas is found to contain 90.5 % methane, 5.8% ethane and rest nitrogen. Calculate the followings: i) The partial pressure of nitrogen? ii) The pure-component volume of ethane in 10 m 3 of the gas

Answer 1

Answer:

Natural gas is piped from the well at 300K and 400 kPa. The gas is found to contain 90.5 % methane, 5.8% ethane and rest nitrogen. Calculate the followings: i) The partial pressure of nitrogen? ii) The pure-component volume of ethane in 10 m 3 of

Answer 2

GIVEN,

temperature= 300k, pressure= 400kpa, the gas contains= 90.5% methane,5.8% ethane, rest nitrogen.

TO FIND,

i) The partial pressure of nitrogen?

ii) The pure-component volume of ethane in 10 m 3 of the gas

SOLUTION,

let us first find the mole % of the nitrogen in the gas, we get,

⇒100= 90.5+5.8+x ( where x is the % of nitrogen in the gas)

⇒x= 100- 96.3

∴ x= 3.7% is the presence of nitrogen.

now mole fraction of nitrogen(N₂)

 $=\frac{mole of N2}{total moles}\\\\=\frac{3.7}{100}\\\\=0.037$

i) Partial pressure of (N₂)

$={mole fraction of(N2) }* pressure\\\\= 0.037* 400\\\\=14.8 kPa$

ii) pure component of ethane= mole fraction od ethane* total volume

                                               =$\frac{5.8}{100} *10$

                                               = 0.58 ml.

HENCE  PARTIAL PRESSURE OF NITROGEN IS 14.8 kPa AND PURE COMPONENT OF ETHANE IS 0.58 ML.