Question

natural number is greater than twice its square root by 3 find the number​

Answer 1

Answer:

let the no be x

So expression will be :

x=2√x+3

x-3=2√x

squaring both sides;

(x-3)2=(2√x)2

x2 +6x-9=4x

x2+2x-9=0

Using quadratic formula;

x=-b±√4ac-b2 ÷2a

x=-2±√8-4 ÷2

x=-2±2 ÷2

taking +ve sign

x=0

taking -ve sign

x=-2

So,

a natural no can't be negative.

Thus,

x=0